You can put this solution on YOUR website! How much water must be added to 6 ounces of a 20% acid solution to obtain a 15% acid solution?
:
Let x = amt of water
:
Write an amt of acid equation, (the amt of acid remains the same only the percent changes)
.20(6) = .15(x+6)
1.2 = .15x + .9
1.2 - .9 = .15x
.3 = .15
x =
x = 2 oz of pure water required
:
:
Prove this by finding the amt of acid in each mixture
.2(6) = 1.2
.15(2+6) = 1.2