SOLUTION: The vertices of the triangle are A(6,1), B(6,7) and C(10,7) show that the triangle is right angled and find it's sides?

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Question 446465: The vertices of the triangle are A(6,1), B(6,7) and C(10,7) show that the triangle is right angled and find it's sides?
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
x1 y1 x2 y2
d= sqrt%28%28y2-y1%29%5E2%2B%28x2-x1%29%5E2%29
6 1 6 7
d(AB)= sqrt%28%287-1%29%5E2%2B%286-6%29%5E2%29
d= sqrt%28%286%29%5E2%09%2B%280%29%5E2%29
d= sqrt%28%2836%29%29
d(AB)= 6.00
x1 y1 x2 y2
d(BC)= sqrt%28%28y2-y1%29%5E2%2B%28x2-x1%29%5E2%29
10 7 6 7
d= sqrt%28%287-7%29%5E2%2B%286-10%29%5E2%29
d=sqrt%28%280%29%5E2%2B%28-4%29%5E2%29
d= sqrt%28%2816%29%29
d(BC)= 4.00
----
x1 y1 x2 y2
d(CA)= sqrt%28%28y2-y1%29%5E2%2B%28x2-x1%29%5E2%29
10 7 6 1
d= sqrt%28%281-7%29%5E2%2B%286-10%29%5E2%29
d= sqrt%28%28-6%29%5E2%2B%28-4%29%5E2%29
d= sqrt%28%2852%29%29
d(CA)= 7.215

d(AB)^2+d(BC)^2= d(AC)^2 if it is a right triangle
6^2+4^2= 7.215^2
52=52