SOLUTION: A pump can empty a swimming pool at a rate of 35 liters per minute. At that rate, how many days will it take to empty a pool of 10,000 gallons?
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-> SOLUTION: A pump can empty a swimming pool at a rate of 35 liters per minute. At that rate, how many days will it take to empty a pool of 10,000 gallons?
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Question 446417: A pump can empty a swimming pool at a rate of 35 liters per minute. At that rate, how many days will it take to empty a pool of 10,000 gallons? Found 2 solutions by mananth, ikleyn:Answer by mananth(16949) (Show Source):
You can put this solution on YOUR website! 35 liters/minute
10gallons = 10,000*3.2 = 32000 liters
32000/35
914 minutes
1day = 24*60= 1440 minutes
914/1440=0.63 days
You can put this solution on YOUR website! .
A pump can empty a swimming pool at a rate of 35 liters per minute. At that rate, how many days
will it take to empty a pool of 10,000 gallons?
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The " solution " in the post by @mananth is INCORRECT, since his conversion " gallons ---> liters " is incorrect.
The problem itself is a simple arithmetic, and I came to bring a straightforward solution.
1 gallon is 3.78541 liters.
10,000 gallons = 3.78541*10000 = 37854.1 liters.
The rate of draining is 35 liters per minute
The time of draining = = 1081.55 minutes (rounded) = 18.026 hours (rounded).
It is LESS than one day.
It is about 18 hours.
