SOLUTION: factor the expression completely m^3+11m^2+28m please help mee solve ti soonnnn

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Question 446395: factor the expression completely
m^3+11m^2+28m
please help mee solve ti soonnnn
Found 2 solutions by stanbon, lwsshak3:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
m^3+11m^2+28m
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= m[m^2 + 11m + 28]
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= m[m^2+4m+7m+28]
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= m[m(m+4)+7(m+4)]
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= m[(m+4)(m+7)]
======================
Cheers,
Stan H.

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
factor the expression completely
m^3+11m^2+28m
..
m^3+11m^2+28m
m(m^2+11m+28)
m(m+7)(m+4)