SOLUTION: How do I solve this? 125/sin25deg = 150/sinB = c/sinC

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Question 446292: How do I solve this? 125/sin25deg = 150/sinB = c/sinC
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
You can solve for sin(B), and then B.
sin(B) = 150*sin(25)/125
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If it's a triangle, then angle C = 180 - (B + 25)
Solve for C, then for side c.