SOLUTION: A committee consists of 9 men and 14 women. In how many ways can a subcommittee of 3 men and 7 women be chosen?

Algebra ->  Permutations -> SOLUTION: A committee consists of 9 men and 14 women. In how many ways can a subcommittee of 3 men and 7 women be chosen?      Log On


   



Question 446269: A committee consists of 9 men and 14 women. In how many ways can a subcommittee of 3 men and 7 women be chosen?
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
9C3x14C7=
(9x8x7x6!/3x2x6!)x(14x13x12x11x10x9x8x7!/7x6x5x4x3x2x7!)=
(3x4x7)x(2x13x11x2x3x2)=288288 different committees possible..