SOLUTION: how many pounds of candy that sells for $8 per pound must be mixed with 4lbs or candy that sells for $12.50 per pound to create a mixture that sells for $9 per pound?
Algebra ->
Percentage-and-ratio-word-problems
-> SOLUTION: how many pounds of candy that sells for $8 per pound must be mixed with 4lbs or candy that sells for $12.50 per pound to create a mixture that sells for $9 per pound?
Log On
Question 446260: how many pounds of candy that sells for $8 per pound must be mixed with 4lbs or candy that sells for $12.50 per pound to create a mixture that sells for $9 per pound? Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! 8x+12.50(4)=9(x+4)
8x+50=9x+36
14=x
You must mix in 14 lbs of $8 candy to get the desired mixture..