SOLUTION: what is the domain of f(x)=ln(1/x+4). I think it works out to set x+4=0 x=-4 domain is (-inf,-4)u(-4,inf)

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: what is the domain of f(x)=ln(1/x+4). I think it works out to set x+4=0 x=-4 domain is (-inf,-4)u(-4,inf)      Log On


   

Question 445983: what is the domain of f(x)=ln(1/x+4).
I think it works out to set x+4=0
x=-4
domain is (-inf,-4)u(-4,inf)
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29+=+ln+%28+1%2Fx+%2B+4+%29+
There is no such thing as the log of a negative
number. That is like saying +a%5Eb+=+-c+
which is not possible.
Therefore, ++1%2Fx+%2B+4+%3E=+0+
+x+%3C=+-1%2F4+
and
+x+%3E=+0+