SOLUTION: solve this a perimeter of a rectangle is 252ft. the length exceeds width by 50 inches. find the length and width

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Question 445879: solve this a perimeter of a rectangle is 252ft. the length exceeds width by 50 inches. find the length and width
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
2(L+w)=P
L=w+50
2(w+50+w)=3024 Substitute w+50 for L. 252'=3024"
2(2w+50)=3024
4w+100=3024
4w=2924
w=731"
L=781"
.
Ed