SOLUTION: Solve the following system of linear inequalities by graphing. 3x-y<2 x+y>2

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Question 44578: Solve the following system of linear inequalities by graphing.
3x-y<2
x+y>2

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
3x+-+y+%3C+2
x+%2B+y+%3E+2
the 1st one:
-y+%3C+-3x+%2B+2
y+%3E+3x+-+2
the 2nd one:
y+%3E+-x+%2B+2
graph y+=+3x+-+2
and
y+=+-x+%2B+2
+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+3x+-+2%2C+-x+%2B+2%29+
The solution is the space which is to the left of y+=+3x+-+2
and to the right of y+=+-+x+%2B+2
check this. From the graph, it looks like the point (0, 3) falls
in the solution region.
1st equation
3 > 3*0 - 2
3 > -2
TRUE
2nd
3 > -0 + 2
3 > 2
TRUE