You can put this solution on YOUR website! [2y/x]+((2x-y)/y)
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lcm = xy
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Rewrite each fraction with the lcm as its denominator:
[(2y^2/lcm] + [(2x^2-xy)/lcm]
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Combine the numerators over the lcm:
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= [2y^2-xy+2x^2]/xy
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Cheers,
Stan H.
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