SOLUTION: I need some help with a negative coefficient. I need to multiply the following equations. 4x-36/x^2+x multiplied by 3x/9-x This is what I have come up with so far: factoring out

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I need some help with a negative coefficient. I need to multiply the following equations. 4x-36/x^2+x multiplied by 3x/9-x This is what I have come up with so far: factoring out      Log On


   

Question 44549: I need some help with a negative coefficient.
I need to multiply the following equations.
4x-36/x^2+x multiplied by 3x/9-x
This is what I have come up with so far: factoring out the equations I get 4(x-9)/x(x+1)multiplied by 3x/9-x. I can cancel out one x and I can also cancel out the 9-x and the x-9 which will give me a -1. This leaves me with the following equation
12/-1(x+1) which equals 12/-x-1. My question is this: what do I do with the negative coefficient? do I multipy by a -1? and would this give me -12/x+1 or 12/x+1.
thank you for the assistance!
Found 2 solutions by mollydew, stanbon:
Answer by mollydew(1) About Me  (Show Source):
You can put this solution on YOUR website!
yes, u should multiply the equation by the negative coefficient!!

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Will give you -12/(x+1)
The rule is as follows:
Every fraction has three signs:
sign of the fraction
sign of the numerator
sign of the denominator
You may change any two of these signs and still
have the original fraction.
Cheers,
Stan H.