SOLUTION: Solve by completing the square: x2 + 6x + 4 = 0

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Question 44516This question is from textbook INTERMEDIATE ALGEBRA
: Solve by completing the square:
x2 + 6x + 4 = 0 This question is from textbook INTERMEDIATE ALGEBRA

Found 2 solutions by tutorcecilia, atif.muhammad:
Answer by tutorcecilia(2152) About Me  (Show Source):
You can put this solution on YOUR website!
x2 + 6x + 4-4 = 0-4
x^2 + 6x +(6/2)^2 = -4+(6/2)^2
x^2 + 6x +(3)^2 = -4+(3)^2
(x+3)(x+3)= -4+9
(x+3)^2= 5
sqrt[(x+3)^2]= sqrt[5]
x+3=sqrt[5]
x+3-3=-3+sqrt[5]
Answer: x=-3 + sqrt[5]

Answer by atif.muhammad(135) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 + 6x + 4 = 0

(x+3)^2 - 9 +4 = 0
(x+3)^2 = 5
x+3 = +/- SQRT(5)
x = -3 +/- SQRT(5)