SOLUTION: Factor completely. 125a^3 – 27b^3 A) (125a - 3b)(a2 + 15ab + 9b2) B) (5a + 3b2)(25a2 – 15ab + 9b2) C) (5a - 3b)(25a2 + 9b2) D) (5a - 3b)(25a2 + 15ab + 9b2) E) none of the a

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: Factor completely. 125a^3 – 27b^3 A) (125a - 3b)(a2 + 15ab + 9b2) B) (5a + 3b2)(25a2 – 15ab + 9b2) C) (5a - 3b)(25a2 + 9b2) D) (5a - 3b)(25a2 + 15ab + 9b2) E) none of the a      Log On


   

Question 445057: Factor completely.
125a^3 – 27b^3
A) (125a - 3b)(a2 + 15ab + 9b2)
B) (5a + 3b2)(25a2 – 15ab + 9b2)
C) (5a - 3b)(25a2 + 9b2)
D) (5a - 3b)(25a2 + 15ab + 9b2)
E) none of the above
I think its C, but I know it can be factored more because 25 can be 5 and 9 can be 3. I just want to make sure its either C or E.
thanks
PAola


Answer by rwm(914) About Me  (Show Source):
You can put this solution on YOUR website!
D (5a-3b) (25a^2+15ab+9b^2)