SOLUTION: find the approximate value of x in the following equation: 2 log x = log 8

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Question 444742: find the approximate value of x in the following equation: 2 log x = log 8
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
The original equation is equivalent to
log%28x%5E2%29+=+log8
==> x%5E2+=+8, because the log function is 1-to-1
==> x+=+sqrt%288%29, approximately equal to 2.8284, to 4 decimal places.
(Do NOT accept the negative solution, because it won't satisfy the original equation.)