Question 44471: Having problem with my assignment, would someone plesae help me?
Determine the point A(x,y) so that the points A(x,y),B(0,3),C(1,0),D(7,2) will be the vertices of a parallelogram.
Find an equation for the line with y-intercept 3 that is perpendicular to the line y=2/3(actaully the fraction two-thirds)x-4.
Answer by venugopalramana(3286)   (Show Source):
You can put this solution on YOUR website! Having problem with my assignment, would someone plesae help me?
Determine the point A(x,y) so that the points A(x,y),B(0,3),C(1,0),D(7,2) will be the vertices of a parallelogram.
DIAGONAL BISECT EACH OTHER IN A PARALLELOGRAM.HENCE
MID POINT OF AC={(X+1)/2,(Y+0)/2}=MID POINT OF BD ={(0+7)/2,(3+2)/2}
X+1=7....X=6
Y=5
A IS (6,5)
Find an equation for the line with y-intercept 3 that is perpendicular to the line y=2/3(actaully the fraction two-thirds)x-4.
SLOPE OF GIVEN LINE =2/3
SLOPE OF ITS PERPENDICULAR =-3/2
HENCE EQN.IS
Y=MX+C
Y=-3X/2+3
2Y+3X-6=0
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