Question 444481: 3^6x=2^(-x-4)
using base-10 logarithms
Answer by chriswen(106)   (Show Source):
You can put this solution on YOUR website! 3^6x=2^(-x-4)
log3^6x=log2^(-x+4) ... log both sides
6xlog3=(-x+4)log2 ... since, logm^n=nlogm
6xlog3=-xlog2+4log2 ... distribution
6xlog3+xlog2=4log2
x(6log3+log2)=4log2
x=4log2/(6log3+log2) ... now you can just input this into your calculator or you can simplify it more.
x=.380598
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