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| Question 443818:  seven divided by the difference of a number and 2 minus 6 divided by a number plus 2 equals 6 times the reciprocal of the difference of the number squared and 4, whats the number?
 Answer by karaoz(32)
      (Show Source): 
You can put this solution on YOUR website! 
 This is a funny question. I wonder what is the purpose of it.
 Let this jumpy number be called x!
 Then translating the problem statement using algebraic symbols for operators and x for "a number" we have the following:
 7/(x-2) - 6/(x+2) = 6*1/(x2-4). What is x?
 
 Note that the denominators in three fractions are (x-2), (x+2) and (x2-4). Also, note that (x2-4) = (x-2)*(x+2).
 
 After multiplying both sides of the equation by (x2-4), we have:
 7(x2-4)/(x-2) - 6(x2-4)/(x+2) = 6(x2-4)/(x2-4), which becomes:
 7(x-2)(x+2)/(x-2) - 6(x-2)(x+2)/(x+2) = 6, which is the same as
 7(x+2) - 6(x-2) = 6
 
 After expanding the brackets:
 7x + 14 - 6x + 12 = 6
 
 After simplifying the left hand side:
 x + 26 = 6
 
 After taking away 26 from both sides of the equation:
 x = -20.
 
 That's it!
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