SOLUTION: Juan has 24 coins worth $2.80. His coins are nickels, dimes and quarters. The number of dimes equals the sum of number of quarters and nickels. How many dimes does he have?
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Question 443785: Juan has 24 coins worth $2.80. His coins are nickels, dimes and quarters. The number of dimes equals the sum of number of quarters and nickels. How many dimes does he have? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Let n = no. of nickels
Let d = no. of dimes
Let q = no. of quarters
:
Write an equation(s) for each sentence;
:
"Juan has 24 coins worth $2.80."
n + d + q = 24
and
.05n + .10d + .24q = 2.80
:
" The number of dimes equals the sum of number of quarters and nickels."
d = q + n
rearrange to
-n + d - q = 0
Add this to the 1st equation
-n + d - q = 0
n + d + q = 24
------------------adding eliminates n and q, find d
2d = 24
d =
d = 12 dimes, which is all they ask for here.
