SOLUTION: find the vertex, the line of symmetry, the maximum or minimum value of the quatratic function, and graph the functio f(x)=+-2x^2+2x+8 Find the x-coordinate of the vertex is___

Algebra ->  Graphs -> SOLUTION: find the vertex, the line of symmetry, the maximum or minimum value of the quatratic function, and graph the functio f(x)=+-2x^2+2x+8 Find the x-coordinate of the vertex is___       Log On


   

Question 443745: find the vertex, the line of symmetry, the maximum or minimum value of the quatratic function, and graph the functio f(x)=+-2x^2+2x+8
Find the x-coordinate of the vertex is___
Find the y-coordinate of the vertex is__
The equation of the line of symmetry is x=____
The maximum/minimum of f(x)is ___
The value , f(1/2)=17/2 is?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

Note: vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex

f(x)= -2x^2+2x+8

f(x)= -2[(x-.5)^2 -.25] +8

f(x)= -2(x-.5)^2 +.5 +8

f(x)= -2(x-.5)^2 + 8.5  V(.5,8.5) Line of symetry is x = .5

     a = -2 < 0  Parabola opens downward:  f(x) maximum is 8.5

The value , f(1/2) = 17/2 is the maximum value for f(x)



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