SOLUTION: 1. A man bought three dozen of oranges and two dozen of apples. his change from a $10 bill was $1.96. One orange costs more than 10 cents and one apple more than 15 cents. How much

Algebra ->  Systems-of-equations -> SOLUTION: 1. A man bought three dozen of oranges and two dozen of apples. his change from a $10 bill was $1.96. One orange costs more than 10 cents and one apple more than 15 cents. How much      Log On


   

Question 443656: 1. A man bought three dozen of oranges and two dozen of apples. his change from a $10 bill was $1.96. One orange costs more than 10 cents and one apple more than 15 cents. How much does an orange cost?

2. Harry bought 28 more expensive pens in a store, recieving44 cents change in coins from a $ 20 bill plus perhaps some bills. How much were the pens?
Answer by rwm(914) About Me  (Show Source):
You can put this solution on YOUR website!
10.00-1.96=
8.04
o>10
a>15
36o+24a=804
18o+12a=402
9o+6a=201
3o+2a=67
3o>30
2a>30
3x+2y=7
x=1 y=2
3+4=7
o=11 cents per orange
a=17 cents per apple
check
33+34=67
ok
36*11+24*17
396+408=804
ok