SOLUTION: A box contains 5 red, 6 blue, 3 green, and 2 yellow crayons. How many red crayons must be added to the box so that the probability of randomly picking a red crayon is 2/3?
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-> SOLUTION: A box contains 5 red, 6 blue, 3 green, and 2 yellow crayons. How many red crayons must be added to the box so that the probability of randomly picking a red crayon is 2/3?
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Question 443598: A box contains 5 red, 6 blue, 3 green, and 2 yellow crayons. How many red crayons must be added to the box so that the probability of randomly picking a red crayon is 2/3? Answer by swincher4391(1107) (Show Source):
You can put this solution on YOUR website! Our current probability is 5 reds / (5+6+3+2) crayons
or 5/16 .
Let x be the number of crayons needed to be added.
Then,
cross-multiply to get:
