Question 443548: The difference between the squares of two consecutive odd integers is 128. What is the product of the two integers? Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! Let the integers be x and x+2
(x+2)^2-x^2=128
x^2+4x+4-x^2=128
4x+4=128
4x=124
x=31
x+2=33
31*33=1023
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Ed