SOLUTION: "Please help!!! I cannot figure out the answer to this question. I've tried different formulas and still can't get the right answer. If I can find the right formula this will hel

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: "Please help!!! I cannot figure out the answer to this question. I've tried different formulas and still can't get the right answer. If I can find the right formula this will hel      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 443507: "Please help!!!
I cannot figure out the answer to this question. I've tried different formulas and still can't get the right answer. If I can find the right formula this will help out tremendously. Here is the question:

A farm brings 15 tons of watermelon to market. Find a 90% confidence interval for the population mean cash value of this crop. What is the margin of error? Hint: 1 ton is 2000 pounds. (Round your answers to two decimal places.)

Found 2 solutions by MathLover1, stanbon:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

z+=+1.645
= 68.8 ± 1.645 * 19.2 / √(30000)
= 68.8 ± 1.645 * 19.2 / 173.21)
= 0.18
68.8 - 0.18, 68.8 + 0.18
68.62 < µ < 68.98

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A farm brings 15 tons of watermelon to market. Find a 90% confidence interval for the population mean cash value of this crop. What is the margin of error? Hint: 1 ton is 2000 pounds. (Round your answers to two decimal places.)
------
It appears that the sample mean is 15 tons.
No unit price sees to be available.
No standard deviation value is stated.
-----
The margin of error is zs/sqrt(n)
--
For a 90% CI z = 1.645
----
The CI will be 15-1.645s/sqrt(n) < u < 15+1.645s/sqrt(n)
--------------------------------------------------------------
Cheers,
Stan H.