SOLUTION: 3m+12 over m^2-4=-2m^2+3m+6 over m^2-4+2m-4 over m-2

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Question 44337: 3m+12 over m^2-4=-2m^2+3m+6 over m^2-4+2m-4 over m-2
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!

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3m+%2B+12+=+-2m%5E2+%2B+3m+%2B+6+%2B+%282m+-+4%29%28m+%2B+2%29
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3m+%2B+12+=+-2m%5E2+%2B+3m+%2B+6+%2B+2m%5E2+-+8
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12+=+6+-+8
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12+=+-2
Twelve does not equal negative two, so there are no possible solutions.