You can put this solution on YOUR website! Prove that each is an identity
(sin^3 x + cos^3 x)/ (sin x + cos x) = 1 - (sin 2 x/ 2)
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Start with left side
Use sum of cubes
[(sinx+cosx)(sin^2x-sinxcosx+cos^2x)]/(sin x + cos x)
cancel (sin x + cos x) and use identity sin^2+cos^2=1
=1-sinxcosx*(2/2)
=1-(2sinxcosx)/2=1-(sin 2x/2)
left side=right side