SOLUTION: Can you solve this? And explain how?
Three cards are drawn at random without replacement from a standard deck of 52 playing cards. Find the probability that the second and thir
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Three cards are drawn at random without replacement from a standard deck of 52 playing cards. Find the probability that the second and thir
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Question 443260: Can you solve this? And explain how?
Three cards are drawn at random without replacement from a standard deck of 52 playing cards. Find the probability that the second and third cards are black. Answer by swincher4391(1107) (Show Source):
You can put this solution on YOUR website! You start with 52 cards. You draw a card, there is now only 51.
You now draw the second card:
There are two cases:
You drew a black card on the first draw: Then there are only 25 blacks and 51 cards: the probability of drawing a black: 25/51
You drew a red card on the first draw: Then there are 26 blacks still, and 51 cards: the probability of drawing a black: 26/51
Regardless, you have drawn a card, so there are 50 cards left.
If you drew a black card and another black card, then there are 24 blacks left, 50 cards. 24/50 = 12/25
If you drew a red and black, then 25/50 = 1/2
So now we match up
Call event A: The probability of drawing three black cards is (25/51)*(24/50) = 8/34
Call event B:The probability of drawing a red, black, black is (26/51) *(25/50) = 13/51
Add these two probabilities together since either one can happen. P(A or B) = (8/34) + (13/51) = 408/1734 + 442/1734 =
