Question 443181: please help me to solve t^3 -t^2 +t-1 divide t-1 using long division. thank you.
Answer by swincher4391(1107)   (Show Source):
You can put this solution on YOUR website! t-1 | t^3 -t^2 +t -1
How many times does t go into t^3? t^2
(t-1)t^2 = t^3 - t^2
t^3 - t^2 + t -1
-(t^3 - t^2)
=================
0 + t -1
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How many times does t go into t-1? 1
t-1
-(t-1)
======
0
=======
Remainder of 0, then t-1 divides evenly, and you get t^2 + 1.
Let's check this.
(t-1)(t^2+1) ------by foil ----->t^3 - t^2 +t -1
So yes, we're right.
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