SOLUTION: solve by the substitution method,whats the solution of system 4x + 5y =13 and -6x +y =57

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Question 442979: solve by the substitution method,whats the solution of system 4x + 5y =13 and -6x +y =57
Found 2 solutions by swincher4391, MathLover1:
Answer by swincher4391(1107) About Me  (Show Source):
You can put this solution on YOUR website!
Notice that with -6x +y =57, y has a coefficient of 1. This will be a good choice for substitution.
Solve for y.
y = 57+6x
Plug 57+6x back in the other equation where you see y.
4x + 5(57+6x) = 13
4x + 285 + 30x = 13
34x = -272
x=-8
Plug -8 back into either equation.
-6(-8) + y = 57
48 + y = 57
y = 9
So our solution is (-8,9) x=-8y=9.
Let's check to make sure this works.
4(-8) + 5(9) = -32 + 45 = 13
-6(-8) + 9 = 48 + 9 = 57
So it works.
Hope this helped!

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

+4x+%2B+5y+=13.....1
-6x+%2By+=57.......2
----------------------------
-6x+%2By+=57...solve for y
y+=6x%2B57........substitute in 1

+4x+%2B+5%286x%2B57%29+=13.....1....solve for x
+4x+%2B+30x%2B285+=13
+34x=13-285
+34x=-272
+x=-272%2F34
+x=-8
now find y
y+=6%28-8%29%2B57
y+=-48%2B57
y+=9
check:

+4x+%2B+5y+=13.....1
+4%28-8%29+%2B+5%2A9+=13
+-32+%2B+45+=13
+13+=13