SOLUTION: y=(x^3-x)/2 I need to find the intercepts, I know it intercepts the y axis at (0,0) but want to know how to find the x intercepts,I am having trouble when plugging 0 in for y. I

Algebra ->  Graphs -> SOLUTION: y=(x^3-x)/2 I need to find the intercepts, I know it intercepts the y axis at (0,0) but want to know how to find the x intercepts,I am having trouble when plugging 0 in for y. I       Log On


   

Question 442922: y=(x^3-x)/2
I need to find the intercepts, I know it intercepts the y axis at (0,0) but want to know how to find the x intercepts,I am having trouble when plugging 0 in for y. I am thinking they will be square roots. Please help

I was also asked to test this equation for symmetry and determined that it is symmetric with respect to the origin.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

y= (x^3-x)/2 

y-intercept (0,0)

x-intercept (when y=0)

 x^3-x)/2 = 0

 x(x^2-1) = 0

 x(x-1)(x+1)= 0

 x = 0   (0,0)

(x-1)= 0 (1,0)

(x+1)= 0 (-1,0) 



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