SOLUTION: Find the distance between P and Q, given the coordinates below P(7,3), Q(13,11)

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Question 442618: Find the distance between P and Q, given the coordinates below
P(7,3), Q(13,11)
Found 2 solutions by mananth, swincher4391:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
Distance between two points
x1 y1 x2 y2
d= sqrt%28%28y2-y1%29%5E2%2B%28x2-x1%29%5E2%29
7 3 13 11
d= sqrt%28%2811-3%29%5E2%2B%2813-7%29%5E2%29
d= sqrt%28%288%29%5E2%2B%286%29%5E2%29
d= sqrt%28%28100%29%29
d= 10.00

Answer by swincher4391(1107) About Me  (Show Source):
You can put this solution on YOUR website!
You are given two points of the form (x1,y1) and (x2,y2).
The distance formula is sqrt%28%28x%5B2%5D-x%5B1%5D%29%5E2+%2B+%28y%5B2%5D+-+y%5B1%5D%29%5E2%29
So then our distance between PQ would be:
sqrt%28%2813-7%29%5E2+%2B+%2811-3%29%5E2%29+=+sqrt%286%5E2+%2B+8%5E2%29=sqrt%28100%29+=+10