SOLUTION: Find the vertex and focus of the parabola. y^2 = 36x – 216

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Question 442423: Find the vertex and focus of the parabola.
y^2 = 36x – 216


Answer by ewatrrr(24785) About Me  (Show Source):
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Hi

Find the vertex and focus of the parabola.

y^2 = 36x – 216

Note: vertex form of a parabola, x=a%28y-k%29%5E2+%2B+h where(h,k) is the vertex

  x = (1/36)y^2 + 6  V( 6,0) Parabola opening right a = 1/36 > 0

Note: standard form is %28y+-k%29%5E2+=+4p%28x+-h%29, where  the focus is (h + p, k)

 y^2 = 36(x-6)   4p = 36  p = 9

focus(6+9,0)or (15,0)







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