SOLUTION: 20000$ is split into two investments one paying 5% and the other paying 6.5% to the nearest cent how much should be invested in each so the yearly intrest from the 5% investment is
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Question 442367: 20000$ is split into two investments one paying 5% and the other paying 6.5% to the nearest cent how much should be invested in each so the yearly intrest from the 5% investment is double the intrest from 6.5% investment
You can put this solution on YOUR website! let investment at 6.5% be x
Investment at 5 % = (20000-x)
...
5%x= 2*6.5%(20000-x)
multiply by 100
5x=2*6.5(20000-x)
5x=130000-13x
18x=130000
x= 7,222.22 at6. 5%
Balance at 6.5%
You can put this solution on YOUR website! .
20000$ is split into two investments one paying 5% and the other paying 6.5%. To the nearest cent how much should be
invested in each so the yearly interest from the 5% investment is double the interest from 6.5% investment
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The solution in the post by @mananth is incorrect due to arithmetic error.
Below is my correct solution.
let investment at 6.5% be x.
Investment at 5% is (20000-x).
...
0.05*x = 2*0.065*(20000-x)
Multiply by 100 both sides of the equation
5x = 2*6.5(20000-x)
5x = 260000 - 13x
18x = 260000
x = 260000/18 = 14,444.44 dollars invested at 6.5%.
The rest, or 20,000 - 14,444.44 = 5,555.56 dollars invested at 5%.
CHECK. The interest of the 5% investment is 14444.44*0.05 = 722.22.
The interest of the 6.5% investment is 0.065*5555.56 = 361.11.
The interest of the 5% investment is the doubled interest of the 6.5% investment. ! correct !