SOLUTION: Suppose you have two dogs and one flea. The dogs spy one another from opposite ends of an 100-ft driveway and begin to run towards each other, each at a speed of 10 ft per second.
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Question 442285: Suppose you have two dogs and one flea. The dogs spy one another from opposite ends of an 100-ft driveway and begin to run towards each other, each at a speed of 10 ft per second. Starting on one dog, the flea springs back and forth from nose to nose at a speed of 20 feet per second until the dogs collide and flatten him. How far did the flea travel in all? My initial guess was 100ft but then I realized that it would not be possible because the dogs meets at the half-way point of 50ft, so the flea would have to travel once on each dog and began another flight of 5 ft before being flattened. So it would make it 45 ft. I am not sure, nor do i know how what formula to use to get the answer. Could you please help Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! The dogs start 100 feet apart and approach each other at 20 mph (10 + 10).
They run for 5 seconds (100/20)
The flea moves at 20 feet/sec for 5 seconds
5*20 = 100 feet.
