Question 442248: log10(x+3)-log 10x=2 then x =
Answer by ilana(307)   (Show Source):
You can put this solution on YOUR website! log(base10)(x+3)-log(base10)x is the same as log(base10)[(x+3)/x].
So log(base10)[(x+3)/x] = 2.
That means 10^2 = (x+3)/x
So 100 = (x+3)/x
Multiply each side by x.
100x = x + 3
Subtract x from each side.
99x = 3
Divide each side by 99.
x = 3/99
Simplify.
x = 1/33
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