Question 441885: Solve this equation using matrices.
2x-3y+z=5
x+3y+8z=22
3x-y+2z=12
I have already done the augmented matrix.
2 -3 1 5
1 3 8 22
3 -1 2 12
and switched R1 and R2
1 3 8 22
2 -3 1 5
3 -1 2 12
-2R1 + R2 & -3R1+R2
1 3 8 22
0 -9 -15 -39
0 -10 -22 -54
and here is where I get stuck! I know I have to get a 1 in the second row,second column. I just can't seem to do it without fractions. My teacher also provides me with the answer (3,1,2) Answer by rwm(914) (Show Source):
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