SOLUTION: factor completely (m+n)x^2-6x(m+n)+8(m+n)

Algebra ->  Conversion and Units of Measurement -> SOLUTION: factor completely (m+n)x^2-6x(m+n)+8(m+n)      Log On


   

Question 441863: factor completely (m+n)x^2-6x(m+n)+8(m+n)
Answer by rwm(914) About Me  (Show Source):
You can put this solution on YOUR website!
(m+n)x^2-6x(m+n)+8(m+n)
(m+n)(x^2-6x+8)
(x^2-6x+8) can be factored
which factors of 8 add up to -6
-4 and -2
(m+n)(x-4)(x-2)