Question 441786: the volume of a balikbayan box filled with canned goods is 10648 dm3. if each can is 112 mL,how many cans are there in the box? Answer by AHBK(13) (Show Source):
You can put this solution on YOUR website! the volume of the balikbayan is 10648 dm3 which is same as 10648Leters
1L=1000 ml
10648=X
using simple third rule u get:
X=(10648*1000)/1
so X= 10648000 ml
so volume of balikbayan is 10648000 ml
if each can is 112ml
and volume of balikbayan is 10648000 ml
then number of cans in there is equal to (10648000)/(112)
so (10648000)/(112)= 95071.42 cans in there
you can also do it by changing 112ml to leters n then dividing 10648 by the number you get
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