Question 441784: line that passes through the point (1,-3) and is parallel to the line 7x + y = -5.
Answer by sudheerb(5)   (Show Source):
You can put this solution on YOUR website! Given equation of line is 7x + y = -5.
It is in the form of ax + by = c. Slope of this line is -a/b.
Slope of 7x + y = -5 is m = -7.
We know that slopes of two paralel lines are same.
Therefore the slope of line parallel to line 7x + y = -5 is -7.
The required line also passes through point (1,-3).
Therefore equation of line passing through (x1,y1) and having slope m is
y - y1 = m(x - x1)
Here (x1, y1) = (1,-3) and m = -7.
y - (-3) = (-7)(x-1)
y+3 = -7x + 7
Subtract 3 from both sides of equation
y + 3 - 3 = -7x + 7 - 3
y = -7x + 4
Add 7x to both sides of equation
7x + y = -7x + 4 + 7x
7x + y = 4 is the equation of the line.
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