Question 441712: bob is twice as old as sue. ten years ago bob was three times as old as sue was then. find the present ages of sue and bob. Answer by robertb(5830) (Show Source):
You can put this solution on YOUR website! bob = 2s
sue = s
2s - 10 = 3(s-10)
==> 2s - 10 = 3s - 30
==> -10+ 30 = 3s - 2s
==> s = 20, the age of sue now ==> bob is 40 years old now.