SOLUTION: solve by any method you prefer. y^2 - 4y + 3 = 0

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Question 44156: solve by any method you prefer.
y^2 - 4y + 3 = 0
Answer by adamchapman(301) About Me  (Show Source):
You can put this solution on YOUR website!
y^2 - 4y + 3 = 0
Use the quadratic solver y+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
where
a=1
b=-4
c=3
Now y+=+%284+%2B-+sqrt%28+4%5E2-4%2A1%2A3+%29%29%2F2+
y+=+%284+%2B-+sqrt%28+16-12+%29%29%2F2+
y+=+%284+%2B-+sqrt%28+4+%29%29%2F2+
y+=+4%2F2+%2B-+2%2F2+
y+=+2+%2B-+1+
So y=1 or y=3
I hope this helps
P.S. I am trying to start up my own homework help website. I would be extremely grateful if you would e-mail me some feedback on the help you received to adam.chapman@student.manchester.ac.uk