SOLUTION: the excursion boat Holiday travels 35 km upstream and then back again in 4h 48min. if the speed of the Holiday in still water is 15km/h, what is the speed of the current?
how wo
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how wo
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Question 441532: the excursion boat Holiday travels 35 km upstream and then back again in 4h 48min. if the speed of the Holiday in still water is 15km/h, what is the speed of the current?
how would i set up an equation to solve this?? Answer by rwm(914) (Show Source):
You can put this solution on YOUR website! the distance is the same up and down stream
upstream means against the current s-c
downstream is with the current s+c
trip takes 4 48/60 hrs
r*t=d
(s-c)*u=35
(s+c)*d=35
u+d=4 48/60
s=15
we can substitute 15 for s
u=35-d
35-d for u
(15-c)*(35-d)=(15+c)*d
c=5/2 or 2.5 current
d=2
s=15
u=14/5= 2.8
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