SOLUTION: Solve Log(x+2)=-log(x-1)+1 x+2=x-1+1 x-2=x

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Solve Log(x+2)=-log(x-1)+1 x+2=x-1+1 x-2=x      Log On


   

Question 441483: Solve
Log(x+2)=-log(x-1)+1
x+2=x-1+1
x-2=x
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
Log(x+2)=-log(x-1)+1
Log(x+2)+log(x-1) = 1
Log(x+2)(x-1) = 1
(x+2)(x-1) = 10^1
x^2+x-2 = 10
x^2+x-12 = 0
(x+4)(x-3) = 0
x = {-4,3}
You can toss out the -4 (extraneous solution) leaving:
x = 3