SOLUTION: problem is (3y²)(6y-²)= the second squared is - negative -2 how do i work this problem out?

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Question 441350: problem is (3y²)(6y-²)=
the second squared is - negative -2
how do i work this problem out?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

referring to the rules governing exponents:

a%5E0+=+1

%28a%5Ep%29%5Eq+=+a%5E%28p%2Aq%29

root%28a%2Cp%29%2Aroot%28a%2Cq%29+=+root%28a%2Cp%2Aq%29

x%5Em%2Fx%5En=x%5E%28m-n%29

%28+x%5Em+%29%28+x%5En+%29+=+x%5E%28+m+%2B+n+%29 ***

   +%283y%5E2%29%286y%5E%28-2%29%29=++18y%5E%282-2%29+=+18y%5E0+=+18+