SOLUTION: I need help by solving this quatric equastion 4x^4-37x^2+9=0 Thank you!
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Question 441186
:
I need help by solving this quatric equastion
4x^4-37x^2+9=0
Thank you!
Answer by
shree840(260)
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4x^4-37x^2+9=0
4x^4-36x^2-x^2+9=0
4x^2(x2-9)-1(x^2-9)=0
(4x^2-1)(x^2-1)=0
(2x+1)(2x-1)(x+1)(x-1)=0
2x+1=0 or x=-1/2
2x-1=0 x=1/2
x+1=0 or x=-1
x-1=0 or x=1 ANS