SOLUTION: log<SUB>7</SUB>(x^2+x)=log<SUB>7</SUB>56 Im supposed to solve. but I don't know where to begin.

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: log<SUB>7</SUB>(x^2+x)=log<SUB>7</SUB>56 Im supposed to solve. but I don't know where to begin.       Log On


   



Question 441079: log7(x^2+x)=log756
Im supposed to solve. but I don't know where to begin.

Found 2 solutions by stanbon, nerdybill:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
log7(x^2+x)=log7(56)
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x^2+x = 56
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x^2+x-56 = 0
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Factor:
(x-7)(x+8) = 0
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x = 7 or x = -8
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Cheers,
Stan H.
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Answer by nerdybill(7384) About Me  (Show Source):