SOLUTION: The time spent waiting in the line is approximately normally distributed. The mean waiting time is 7 minutes and the standard deviation of the waiting time is 2 minutes. Find t
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Question 440866: The time spent waiting in the line is approximately normally distributed. The mean waiting time is 7 minutes and the standard deviation of the waiting time is 2 minutes. Find the probability that a person will wait for less than 11 minutes. (Round your answer to 4 decimal places) Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The time spent waiting in the line is approximately normally distributed. The mean waiting time is 7 minutes and the standard deviation of the waiting time is 2 minutes. Find the probability that a person will wait for less than 11 minutes. (Round your answer to 4 decimal places)
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z(11) = (11-7)/2 = 2
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P(x < 11) = P(z < 2) = 0.97725
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Cheers,
Stan H.
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