SOLUTION: please help me solve this: f(x)=1/2x^2-6....also need to know the minimum and maximum point as well as the equation of the line of symmetry and the distance and direction of the tr

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: please help me solve this: f(x)=1/2x^2-6....also need to know the minimum and maximum point as well as the equation of the line of symmetry and the distance and direction of the tr      Log On


   

Question 440801: please help me solve this: f(x)=1/2x^2-6....also need to know the minimum and maximum point as well as the equation of the line of symmetry and the distance and direction of the translation of the parabola from the origin, then state whether the parabola opens upward or downward
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

Using the vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex

f(x)=1/2x^2-6

 1) parabola opens upward a = 1/2 > 0  Vertex Pt(0,-6) is a minumum pt

 2) Line of symetry is the  y -axis

 3) relative to the the translation from the origin: down 6.