SOLUTION: There were 34,000 people at a ballgame in Los Angeles. The day's receipts from $13 reserved seats and $6 general-admission seats were $239,000. How many of each type of seat were s

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Question 440780: There were 34,000 people at a ballgame in Los Angeles. The day's receipts from $13 reserved seats and $6 general-admission seats were $239,000. How many of each type of seat were sold?
whats the steps to getting
g=29000
r=5000 ??
Found 2 solutions by htmentor, stanbon:
Answer by htmentor(1343) About Me  (Show Source):
You can put this solution on YOUR website!
Let R = the number of reserved seats sold
Then 34000 - R = the number of general-admission seats sold
We can write the following equation for the day's receipts:
13R + 6(34000-R) = 239000
Solve for R:
7R = 35000
Therefore R = 5000
So the number of G-A tickets sold is 34000 - 5000 = 29000

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
There were 34,000 people at a ballgame in Los Angeles. The day's receipts from $13 reserved seats and $6 general-admission seats were $239,000. How many of each type of seat were sold?
whats the steps to getting
g=29000
r=5000 ??
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Quantity Equation: r + g = 34000
Value Equation:::13r +6g = 239,000
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Multiply thru 1st by 13
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13r + 13g = 13*34000
13r + 6g = 239,000
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Subtract and solve for "g":
7g = 216000
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g = 30857 (# of general admission tickets sold)
r + g = 34000
r = 3143 (# of reserved admission tickets sold)
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Cheers,
Stan H.
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