SOLUTION: find the foci of the ellipse with the equation: x^2\16 + y^2/36=1

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Question 440664: find the foci of the ellipse with the equation:
x^2\16 + y^2/36=1
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

 Standard Form of an Equation of an Ellipse is %28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1+

where Pt(h,k) is the center and a and b  are the respective vertices distances from center.

find the foci of the ellipse with the equation:

x%5E2%2F16+%2B+y%5E2%2F36=1   | Center(0,0)

 a = 4 and b = 6  f = sqrt(36-16) = sqrt(20) = ±2sqrt(5)

ellipse with foci (0, ±2sqrt(5))